Foundations-of-Computer-Science완벽한인증덤프 - Foundations-of-Computer-Science완벽한시험자료

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Foundations-of-Computer-Science완벽한 시험자료, Foundations-of-Computer-Science 100％시험패스 공부자료

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최신 Courses and Certificates Foundations-of-Computer-Science 무료샘플문제 (Q38-Q43):

질문 # 38
Which line of code below contains an error in the use of NumPy?

정답：B

설명：
The NumPy library provides arrays and efficient numerical operations, including sorting. However, NumPy doesnotprovide a function named np.quicksort. That is the API misuse in the code, making option A the correct answer. In NumPy, sorting is commonly performed using np.sort(arr) (which returns a sorted copy) or arr.sort() (which sorts in-place). If a specific algorithm is desired, NumPy exposes it through the kind parameter, such as np.sort(arr, kind="quicksort"), kind="mergesort", or kind="heapsort". Textbooks present this as a typical design: a single sorting interface with selectable strategies, rather than separate top-level functions per algorithm name.
Option C is correct and necessary: import numpy as np is standard convention. Option B is also correct:
printing a variable is valid assuming it exists. Option D, written as arr = np.array([3, 2, 0, 1]), is valid NumPy usage for constructing a 1D array from a Python list.
A subtle point taught in scientific computing courses is that library APIs matter as much as syntax: you can write perfectly valid Python that still fails if you call a function that the library does not define. In this case, the fix is to replace np.quicksort(arr) with np.sort(arr) or np.sort(arr, kind="quicksort") depending on whether you need to specify the algorithm.


질문 # 39
What is the main advantage of using NumPy arrays over regular Python lists for data analysis?

정답：D

설명：
The primary advantage of NumPy arrays in data analysis is their support for fast, vectorized computation over whole collections of numeric data. A NumPy `ndarray` stores elements in a contiguous memory block with a single, fixed data type, enabling efficient low-level operations implemented in optimized C/Fortran code. As a result, expressions like `arr + 5`, `arr * arr`, or `np.mean(arr)` operate over the entire array without explicit Python loops. This style is commonly called **vectorization**, and it is a central theme in scientific computing textbooks because it is both clearer to read and significantly faster for large datasets.
Option A describes a property of Python lists, not NumPy arrays. Python lists can mix types freely, but this flexibility comes with overhead. Option B is true-NumPy arrays typically hold a single dtype-but it is not the main advantage; it is more of an implementation feature that enables speed and memory efficiency.
Option D is not a defining advantage; both lists and arrays can be concatenated, and NumPy provides dedicated functions such as `np.concatenate`, but concatenation is not the core reason NumPy dominates data analysis workflows.
# Because NumPy operations are applied element-wise across entire arrays and can leverage CPU vector instructions and efficient memory access patterns, they form the foundation for higher-level tools like pandas, SciPy, and many machine learning libraries. This is why the best answer is that NumPy arrays can perform calculations over entire collections of values.


질문 # 40
What is the expected result of running the following code: list1[0] = "California"?

정답：A

설명：
Python lists are mutable sequences, which means elements can be changed in place after the list has been created. The expression list1[0] = "California" uses indexing to target the element at position 0 (the first element, because Python uses zero-based indexing) and assignment (=) to replace that element with a new value. As a result, the list keeps the same length, but its first entry becomes "California".
This operation does not create a new list (so option A is incorrect); it modifies the existing list object referenced by list1. It also does not append to the end of the list (so option C is incorrect). Appending would use methods like list1.append("California"). Option D is not meaningful in Python list semantics; assignment to a single index replaces exactly one element rather than "adding a second element to the line." Textbooks highlight this difference between mutable and immutable sequence types. For example, strings are immutable, so you cannot assign to some_string[0]. Lists, however, are designed for collections that change over time, supporting updates, insertions, deletions, and reordering. Index assignment is fundamental for many algorithms: updating an array-like buffer, modifying a dataset row, replacing incorrect values, or implementing in-place transformations efficiently.


질문 # 41
What is a correct call to the linear search defined as def linear_search(customersList, search_value): ?

정답：B

설명：
A function definition in Python specifies a function name and a list of parameters. Here, def linear_search (customersList, search_value): defines a function named linear_search that requirestwo argumentswhen called: a list (or sequence) of customer items and the value being searched for. A correct call must therefore supply both arguments in the same order: linear_search(customersList, search_value). Option B is correct because it calls the function properly and then prints the returned result.
Textbooks describe linear search as scanning the list from the beginning to the end, comparing each element to search_value until a match is found or the list ends. The function typically returns an index (e.g., position of the match) or a Boolean, or possibly -1/None if not found. Wrapping the call in print(...) is a standard way to display the returned value for testing or demonstration.
Option A is incorrect because it calls a different function name, not linear_search. Option C is incorrect because linear_search() would attempt to call the function with zero arguments, which would raise a TypeError, and then it tries to call the result as if it were another function. Option D uses a different function name (search_linear) and also contains a spelling mismatch compared to the given definition.


질문 # 42
What is the alternative way to access the third element of the first row in np_2d?

정답：A

설명：
NumPy arrays use zero-based indexing, meaning counting starts at 0 rather than 1. In a 2D NumPy array, indexing is typically written in the form array[row_index, column_index]. The first index selects the row, and the second index selects the column. Therefore, the "first row" corresponds to row index 0. Within that row, the "third element" corresponds to column index 2, because the columns are indexed 0, 1, 2, 3, and so on.
So, np_2d[0, 2] directly selects the element at row 0 and column 2, which is the third element in the first row.
This is considered an "alternative" to approaches like two-step indexing (np_2d[0][2]), and it is the standard idiom taught for multi-dimensional NumPy arrays.
The other choices point to different locations. np_2d[1, 3] is the fourth element of the second row, not the third element of the first row. np_2d[2, 0] and np_2d[3, 1] attempt to access the third or fourth row, which would often be out of bounds in a small 2-row example and would raise an IndexError. Correct indexing is a cornerstone of array programming because it determines which observation, feature, or matrix entry your computations will use.


질문 # 43
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